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Fetch the last element of a list
Given the list 
ruby
ruby
ruby
ruby
java
perl
perl
groovy 1.0+
scala
scala
python
cpp C++/CLI .NET 2.0
fsharp
fsharp
fsharp
erlang
erlang
erlang
erlang
ocaml
ocaml
csharp .NET 2.0
csharp .NET 3.5 & C# 3.0
php
php
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[Red, Green, Blue], access the last element ('Blue')
['Red', 'Green', 'Blue'][-1]
['Red', 'Green', 'Blue'].at(-1)
['Red', 'Green', 'Blue'].last
['Red', 'Green', 'Blue'].fetch(-1)
String result = list.get(list.size() - 1);
qw(Red Green Blue)[-1];
@list = qw(Red Green Blue);
$list[-1];
$list[-1];
list = ['Red', 'Green', 'Blue']
result = list[-1]
result = list[-1]
val result = list.last
val result = (list.drop(list.length - 1)).head
list = ['Red', 'Green', 'Blue']
list[-1]
list[-1]
String^ result = list[list->Count - 1];
let last list =
let rec last' list' =
match list' with
| [x] -> x
| x :: xs -> last' xs
if List.is_empty list then failwith "empty list" else last' list
// ------
let result = last list
let rec last' list' =
match list' with
| [x] -> x
| x :: xs -> last' xs
if List.is_empty list then failwith "empty list" else last' list
// ------
let result = last list
let result = (List.nth list ((List.length list) - 1))
let result = (List.hd (List.rev list))
Result = lists:last(List),
Result = last(List),
Result = hd(lists:reverse(List)),
Result = lists:nth(length(List), List),
let list = [ "Red"; "Green"; "Blue" ] in
let last = List.nth list ( (List.length list) - 1 );;
let last = List.nth list ( (List.length list) - 1 );;
let list = [ "Red"; "Green"; "Blue" ] in
let last = List.hd (List.rev list);;
let last = List.hd (List.rev list);;
string[] items = new string[] { "Red", "Green", "Blue" };
List<string> list = new List<string>(items);
string last = list[list.Count - 1]; // "Blue"
List<string> list = new List<string>(items);
string last = list[list.Count - 1]; // "Blue"
// Make sure you import the System.Linq namespace.
// This is not the preferred way of finding the last element if you are using Lists.
string[] items = new string[] { "Red", "Green", "Blue" };
IEnumerable<string> list = new List<string>(items);
string last = list.Last(); // "Blue"
// This is not the preferred way of finding the last element if you are using Lists.
string[] items = new string[] { "Red", "Green", "Blue" };
IEnumerable<string> list = new List<string>(items);
string last = list.Last(); // "Blue"
$list = array("Red", "Green", "Blue");
$last = array_pop($list);
// Be aware of that $list only contains two elements now - not three
$last = array_pop($list);
// Be aware of that $list only contains two elements now - not three
$list = array("Red", "Green", "Blue");
$last = $list[count($list)-1];
$last = $list[count($list)-1];
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