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Replacing a conditional with many branches with a switch/case statement
Many languages support more compact forms of branching than just if ... then ... else such as switch or case or match. Use such a form to add an appropriate placing suffix to the numbers 1..40, e.g. 1st, 2nd, 3rd, 4th, ..., 11th, 12th, ... 39th, 40th
ruby
java
perl
groovy
scala
python
cpp Turbo C++
fsharp
erlang
php
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def suffixed(number)
last_digit = number.to_s[-1..-1].to_i
suffix = case last_digit
when 1 then 'st'
when 2 then 'nd'
when 3 then 'rd'
else 'th'
end
suffix = 'th' if (11..13).include?(number)
"#{number}#{suffix}"
end
(1..40).each {|n| puts suffixed(n) }
last_digit = number.to_s[-1..-1].to_i
suffix = case last_digit
when 1 then 'st'
when 2 then 'nd'
when 3 then 'rd'
else 'th'
end
suffix = 'th' if (11..13).include?(number)
"#{number}#{suffix}"
end
(1..40).each {|n| puts suffixed(n) }
String[] array = new String[40];
for(int n = 1; n <= array.length; n++)
array[n-1] = Integer.toString(n);
for(int n = 0; n < array.length; n++)
{
int y = Integer.parseInt(array[n]);
if(array[n].length() > 1)
y = Integer.parseInt(array[n].substring(1));
switch(y)
{
case 1: {array[n] += "st"; break;}
case 2: {array[n] += "nd"; break;}
case 3: {array[n] += "rd"; break;}
default: array[n] += "th";
}
}
for(int n = 1; n <= array.length; n++)
array[n-1] = Integer.toString(n);
for(int n = 0; n < array.length; n++)
{
int y = Integer.parseInt(array[n]);
if(array[n].length() > 1)
y = Integer.parseInt(array[n].substring(1));
switch(y)
{
case 1: {array[n] += "st"; break;}
case 2: {array[n] += "nd"; break;}
case 3: {array[n] += "rd"; break;}
default: array[n] += "th";
}
}
sub suffix {
my $n = shift;
return 'th' if $n % 100 >= 4 && $n % 100 <= 20;
return 'st' if $n % 10 == 1;
return 'nd' if $n % 10 == 2;
return 'rd' if $n % 10 == 3;
return 'th';
}
foreach my $n (1..40) {
print $n.suffix($n)."\n";
}
my $n = shift;
return 'th' if $n % 100 >= 4 && $n % 100 <= 20;
return 'st' if $n % 10 == 1;
return 'nd' if $n % 10 == 2;
return 'rd' if $n % 10 == 3;
return 'th';
}
foreach my $n (1..40) {
print $n.suffix($n)."\n";
}
def suffix(n) {
switch(n) {
case { n % 100 in 4..20 } : return 'th'
case { n % 10 == 1 } : return 'st'
case { n % 10 == 2 } : return 'nd'
case { n % 10 == 3 } : return 'rd'
default : return 'th'
}
}
(1..40).each { n ->
println "$n${suffix(n)}"
}
switch(n) {
case { n % 100 in 4..20 } : return 'th'
case { n % 10 == 1 } : return 'st'
case { n % 10 == 2 } : return 'nd'
case { n % 10 == 3 } : return 'rd'
default : return 'th'
}
}
(1..40).each { n ->
println "$n${suffix(n)}"
}
object FourToTwenties {
def unapply (n: Int) = (4 to 20).contains(n % 100)
}
def suffix (n: Int) = {
n match {
case FourToTwenties() => "th"
case n if n % 10 == 1 => "st"
case n if n % 10 == 2 => "nd"
case n if n % 10 == 3 => "rd"
case _ => "th"
}
}
for (n <- 1 to 40) {
println(n.toString + suffix(n))
}
def unapply (n: Int) = (4 to 20).contains(n % 100)
}
def suffix (n: Int) = {
n match {
case FourToTwenties() => "th"
case n if n % 10 == 1 => "st"
case n if n % 10 == 2 => "nd"
case n if n % 10 == 3 => "rd"
case _ => "th"
}
}
for (n <- 1 to 40) {
println(n.toString + suffix(n))
}
def affix(num):
num = num == 1 and str(num) + 'st' or num == 2 and str(num) + 'nd' or \
num == 3 and str(num) +'rd' or str(num) + 'th'
return num
print [affix(x) for x in xrange(1,41)]
num = num == 1 and str(num) + 'st' or num == 2 and str(num) + 'nd' or \
num == 3 and str(num) +'rd' or str(num) + 'th'
return num
print [affix(x) for x in xrange(1,41)]
#include<iostream.h>
#include<conio.h>
void main()
{
clrscr();
int num,i,x;
cout<<"Enter the range:";
cin>>num;
for(i=1;i<=num;i++)
{
x=i%10;
switch(i)
{
case 11:
case 12:
case 13:cout<<i<<"th ";
continue;
}
switch(x)
{
case 1: cout<<i<<"st ";break;
case 2: cout<<i<<"nd ";break;
case 3: cout<<i<<"rd ";break;
default: cout<<i<<"th ";
}
}
getch();
}
#include<conio.h>
void main()
{
clrscr();
int num,i,x;
cout<<"Enter the range:";
cin>>num;
for(i=1;i<=num;i++)
{
x=i%10;
switch(i)
{
case 11:
case 12:
case 13:cout<<i<<"th ";
continue;
}
switch(x)
{
case 1: cout<<i<<"st ";break;
case 2: cout<<i<<"nd ";break;
case 3: cout<<i<<"rd ";break;
default: cout<<i<<"th ";
}
}
getch();
}
let suffix = function
| n when n > 10 && n < 20 -> "th"
| n when n % 10 = 1 -> "st"
| n when n % 10 = 2 -> "nd"
| n when n % 10 = 3 -> "rd"
| _ -> "th"
seq { 1 .. 40 }
|> Seq.iter (fun n -> printfn "%i%s" n (suffix n))
| n when n > 10 && n < 20 -> "th"
| n when n % 10 = 1 -> "st"
| n when n % 10 = 2 -> "nd"
| n when n % 10 = 3 -> "rd"
| _ -> "th"
seq { 1 .. 40 }
|> Seq.iter (fun n -> printfn "%i%s" n (suffix n))
Suffix = case Num of
N when N > 10, N < 20 -> "th";
N when N rem 10 =:= 1 -> "st";
N when N rem 10 =:= 2 -> "nd";
N when N rem 10 =:= 3 -> "rd";
_ -> "th"
end,
io_lib:format("~w~s", [Num, Suffix])
N when N > 10, N < 20 -> "th";
N when N rem 10 =:= 1 -> "st";
N when N rem 10 =:= 2 -> "nd";
N when N rem 10 =:= 3 -> "rd";
_ -> "th"
end,
io_lib:format("~w~s", [Num, Suffix])
function suffix($n) {
switch ($n) {
case ($n % 100 >= 4) && ($n % 100 <= 20):
return 'th';
case $n % 10 == 1:
return 'st';
case $n % 10 == 2:
return 'nd';
case $n % 10 == 3:
return 'rd';
default:
return 'th';
}
}
for ($n=1; $n<=40; $n++) {
echo $n . suffix($n) ."\n";
}
switch ($n) {
case ($n % 100 >= 4) && ($n % 100 <= 20):
return 'th';
case $n % 10 == 1:
return 'st';
case $n % 10 == 2:
return 'nd';
case $n % 10 == 3:
return 'rd';
default:
return 'th';
}
}
for ($n=1; $n<=40; $n++) {
echo $n . suffix($n) ."\n";
}
Submit a new solution for ruby, java, perl, groovy ...
