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Check if a string matches with groups
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There is 1 other solution in haskell
"two" if "one two three" matches /one (.*) three/
(if-let [groups (re-matches #"one (.*) three" "one two three")]
(println (second groups)))
(println (second groups)))
Match^ match = Regex::Match("one two three", "one (.*) three");
if (match->Success) Console::WriteLine("{0}", match->Groups[1]->Captures[0]);
if (match->Success) Console::WriteLine("{0}", match->Groups[1]->Captures[0]);
cmatch what;
if (regex_match("one two three", what, regex("one (.*) three")))
cout << what[1] << endl;
if (regex_match("one two three", what, regex("one (.*) three")))
cout << what[1] << endl;
using System;
using System.Text.RegularExpressions;
public class RegexBackReference {
public static void Main() {
var oneTwoThree = "one two three";
var pattern = "one (.*) three";
Match match = Regex.Match(oneTwoThree, pattern);
// group 0 is the entire match. 1 is the first backreference
Console.WriteLine(match.Groups[1]);
}
}
using System.Text.RegularExpressions;
public class RegexBackReference {
public static void Main() {
var oneTwoThree = "one two three";
var pattern = "one (.*) three";
Match match = Regex.Match(oneTwoThree, pattern);
// group 0 is the entire match. 1 is the first backreference
Console.WriteLine(match.Groups[1]);
}
}
case re:run("one two three", "one (.*) three", [{capture, [1], list}]) of {match, Res} -> hd(Res) end.
m := Regex<|one (.*) three|>.matcher("one two three")
if (m.matches)
echo("${m.group(1)}")
if (m.matches)
echo("${m.group(1)}")
let regmatch = (Regex.Match("one two three", "one (.*) three"))
if regmatch.Success then (printfn "%s" (regmatch.Groups.[1].Captures.[0].ToString()))
if regmatch.Success then (printfn "%s" (regmatch.Groups.[1].Captures.[0].ToString()))
re, _ := regexp.Compile("one (.*) three")
groups := re.FindStringSubmatch("one two three")
if len(groups) > 0 {
fmt.Println(groups[1])
}
groups := re.FindStringSubmatch("one two three")
if len(groups) > 0 {
fmt.Println(groups[1])
}
matcher = ("one two three" =~ /one (.*) three/)
if (matcher) println matcher[0][1]
if (matcher) println matcher[0][1]
match = "one two three".find("one (.*) three") { it[1] }
if (match) println match
if (match) println match
Pattern pattern = Pattern.compile("one (.*) three");
Matcher matcher = pattern.matcher("one two three");
if (matcher.matches()) {
System.out.println(matcher.group(1));
}
Matcher matcher = pattern.matcher("one two three");
if (matcher.matches()) {
System.out.println(matcher.group(1));
}
#load "str.cma" ;;
let s = "one two three" in
if Str.string_match (Str.regexp "one \\(.*\\) three") s 0 then
print_string (Str.matched_group 1 s)
let s = "one two three" in
if Str.string_match (Str.regexp "one \\(.*\\) three") s 0 then
print_string (Str.matched_group 1 s)
print $1 if "one two three"=~/^one (.*) three$/
preg_match('/one (.*) three/', 'one two three', $matches);
echo $matches[1];
echo $matches[1];
ereg('one (.*) three', 'one two three', $regs);
echo $regs[1];
echo $regs[1];
match = re.match(r'one (.*) three', 'one two three')
if match:
print match.group(1)
if match:
print match.group(1)
puts $1 if "one two three"=~/^one (.*) three$/
val m = Pattern.compile("one (.*) three").matcher("one two three")
if (m.matches) println(m.group(1))
if (m.matches) println(m.group(1))
Submit a new solution for clojure, cpp, csharp, erlang ...
There is 1 other solution in haskell
