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Parse a date and time from a string

Given the string "2008-05-06 13:29", parse it as a date representing 6th March, 2008 1:29:00pm in the local time zone.
clojure
(.. (SimpleDateFormat. "yyyy-MM-dd HH:mm")
(parse "2008-05-06 13:29"))

Display information about a date

Display the day of month, day of year, month name and day name of the day 8 days from now.
clojure
(let [cal (Calendar/getInstance)]
(.add cal Calendar/DAY_OF_YEAR 8)
(println (.format (SimpleDateFormat. "d, D, MMMM, EEEE")
(.getTime cal))))

Display a date in different locales

Display a language/locale friendly version of New Year's Day for 2009 for several languages/locales. E.g. for languages English, French, German, Italian, Dutch the output might be something like:

Thursday, January 1, 2009
jeudi 1 janvier 2009
giovedì 1 gennaio 2009
Donnerstag, 1. Januar 2009
donderdag 1 januari 2009

(Indicate in comments where possible if any language specific or operating system configuration needs to be in place.)
clojure
(let [time (.getTime (GregorianCalendar. 2009 Calendar/JANUARY 1))]
(doseq [locale ["en" "fr" "it" "de" "nl"]]
(println (.format (DateFormat/getDateInstance DateFormat/FULL
(Locale. locale))
time))))

Display the current date and time

Create a Date object representing the current date and time. Print it out.
If you can also do this without creating a Date object you can show that too.
clojure
(import 'java.util.Date)

(println (str (Date.)))
(prn (java.util.Date.))