View Problem
Perform an action multiple times based on a boolean condition, checked after the first action (DO .. WHILE)
Simulate rolling a die until you get a six. Produce random numbers, printing them until a six is rolled. An example output might be 
erlang
erlang
fantom
csharp .Net 1.1 or higher
Submit a new solution for erlang, fantom, or csharp
There are 14 other solutions in additional languages (clojure, cpp, fsharp, groovy ...)
"4,2,1,2,6"
Pred = fun (DiceRoll) -> DiceRoll =/= 6 end,
Action = fun (DiceRoll) -> io:format("~B,", [DiceRoll]), dice_roll() end,
do_while(Pred, Action, dice_roll()).
Action = fun (DiceRoll) -> io:format("~B,", [DiceRoll]), dice_roll() end,
do_while(Pred, Action, dice_roll()).
-module(dice).
-export([start/0]).
start() ->
roll(dice_roll()).
roll(6) ->
io:format("6~n", []);
roll(N) ->
io:format("~B,", [N]),
roll(dice_roll()).
dice_roll() -> random:uniform(6).
-export([start/0]).
start() ->
roll(dice_roll()).
roll(6) ->
io:format("6~n", []);
roll(N) ->
io:format("~B,", [N]),
roll(dice_roll()).
dice_roll() -> random:uniform(6).
rnd := 0
while(rnd != 6) {
rnd = Int.random(1..6)
Env.cur.out.print(rnd)
if (rnd != 6)
Env.cur.out.print(",")
}
echo
while(rnd != 6) {
rnd = Int.random(1..6)
Env.cur.out.print(rnd)
if (rnd != 6)
Env.cur.out.print(",")
}
echo
System.Random die = new System.Random();
int roll;
do
{
roll = die.Next(1, 6);
Console.Write(roll);
if (roll < 6) Console.Write(",");
}
while (roll != 6);
int roll;
do
{
roll = die.Next(1, 6);
Console.Write(roll);
if (roll < 6) Console.Write(",");
}
while (roll != 6);
Submit a new solution for erlang, fantom, or csharp
There are 14 other solutions in additional languages (clojure, cpp, fsharp, groovy ...)
