View Problem

Check if a string matches with groups

Display "two" if "one two three" matches /one (.*) three/
DiskEdit
erlang 12B3+
case re:run("one two three", "one (.*) three", [{capture, [1], list}]) of {match, Res} -> hd(Res) end.
ExpandDiskEdit
fsharp
let regmatch = (Regex.Match("one two three", "one (.*) three"))
if regmatch.Success then (printfn "%s" (regmatch.Groups.[1].Captures.[0].ToString()))
ExpandDiskEdit
fantom
m := Regex<|one (.*) three|>.matcher("one two three")
if (m.matches)
echo("${m.group(1)}")
DiskEdit
csharp
using System;
using System.Text.RegularExpressions;

public class RegexBackReference {
public static void Main() {
var oneTwoThree = "one two three";
var pattern = "one (.*) three";

Match match = Regex.Match(oneTwoThree, pattern);

// group 0 is the entire match. 1 is the first backreference
Console.WriteLine(match.Groups[1]);
}
}

Submit a new solution for erlang, fsharp, fantom, or csharp
There are 15 other solutions in additional languages (clojure, cpp, go, groovy ...)