View Problem
Rotate a list
Given a list 
erlang
erlang
fsharp
fantom
groovy 1.5.6
groovy
groovy
Submit a new solution for erlang, fsharp, fantom, or groovy
There are 16 other solutions in additional languages (clojure, cpp, csharp, haskell ...)
["apple", "orange", "grapes", "bananas"], rotate it by removing the first item and placing it on the end to yield ["orange", "grapes", "bananas", "apple"]
N = 1, {Left, Right} = lists:split(N, List), Result = Right ++ Left,
N = 1, Result = rotate(N, List),
let rotate list n =
if n <= 0 then
list
else
let (left, right) = split_at list (n - 1)
right @ left
// ------
let result = (rotate fruit 1)
if n <= 0 then
list
else
let (left, right) = split_at list (n - 1)
right @ left
// ------
let result = (rotate fruit 1)
list := ["apple", "orange", "grapes", "bananas"]
list.add(list.removeAt(0))
list.add(list.removeAt(0))
first = items.head()
items = items.tail() + first
items = items.tail() + first
items = items[1..-1] + items[0]
items = items + items.remove(0)
Submit a new solution for erlang, fsharp, fantom, or groovy
There are 16 other solutions in additional languages (clojure, cpp, csharp, haskell ...)
