View Problem
Perform an action multiple times based on a boolean condition, checked after the first action (DO .. WHILE)
Simulate rolling a die until you get a six. Produce random numbers, printing them until a six is rolled. An example output might be 
fsharp .NET 4
erlang
erlang
clojure
groovy
Submit a new solution for fsharp, erlang, clojure, or groovy
There are 13 other solutions in additional languages (cpp, csharp, fantom, haskell ...)
"4,2,1,2,6"
open System
let rand = Random()
Seq.initInfinite (fun _ -> rand.Next(1, 7))
|> Seq.takeWhile (fun x -> x < 6)
|> fun items -> String.Join(",", items)
|> function s when s = "" -> printfn "6" | s -> printfn "%s,6" s
let rand = Random()
Seq.initInfinite (fun _ -> rand.Next(1, 7))
|> Seq.takeWhile (fun x -> x < 6)
|> fun items -> String.Join(",", items)
|> function s when s = "" -> printfn "6" | s -> printfn "%s,6" s
Pred = fun (DiceRoll) -> DiceRoll =/= 6 end,
Action = fun (DiceRoll) -> io:format("~B,", [DiceRoll]), dice_roll() end,
do_while(Pred, Action, dice_roll()).
Action = fun (DiceRoll) -> io:format("~B,", [DiceRoll]), dice_roll() end,
do_while(Pred, Action, dice_roll()).
-module(dice).
-export([start/0]).
start() ->
roll(dice_roll()).
roll(6) ->
io:format("6~n", []);
roll(N) ->
io:format("~B,", [N]),
roll(dice_roll()).
dice_roll() -> random:uniform(6).
-export([start/0]).
start() ->
roll(dice_roll()).
roll(6) ->
io:format("6~n", []);
roll(N) ->
io:format("~B,", [N]),
roll(dice_roll()).
dice_roll() -> random:uniform(6).
(loop [r (rand-int 6)]
(if (= r 5)
nil
(do
(println r)
(recur (rand-int 6)))))
(if (= r 5)
nil
(do
(println r)
(recur (rand-int 6)))))
// Groovy has no do..while; use a normal while
int dice = 0
while (dice != 6) {
dice = Math.random() * 6 + 1
print dice
if (dice != 6) print ','
}
int dice = 0
while (dice != 6) {
dice = Math.random() * 6 + 1
print dice
if (dice != 6) print ','
}
Submit a new solution for fsharp, erlang, clojure, or groovy
There are 13 other solutions in additional languages (cpp, csharp, fantom, haskell ...)
