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Check if a string matches with groups

Display "two" if "one two three" matches /one (.*) three/
ExpandDiskEdit
java
Pattern pattern = Pattern.compile("one (.*) three");
Matcher matcher = pattern.matcher("one two three");
if (matcher.matches()) {
System.out.println(matcher.group(1));
}
DiskEdit
csharp
using System;
using System.Text.RegularExpressions;

public class RegexBackReference {
public static void Main() {
var oneTwoThree = "one two three";
var pattern = "one (.*) three";

Match match = Regex.Match(oneTwoThree, pattern);

// group 0 is the entire match. 1 is the first backreference
Console.WriteLine(match.Groups[1]);
}
}
ExpandDiskEdit
cpp C++/CLI .NET 2.0
Match^ match = Regex::Match("one two three", "one (.*) three");
if (match->Success) Console::WriteLine("{0}", match->Groups[1]->Captures[0]);
ExpandDiskEdit
cpp
cmatch what;
if (regex_match("one two three", what, regex("one (.*) three")))
cout << what[1] << endl;
DiskEdit
clojure
(if-let [groups (re-matches #"one (.*) three" "one two three")]
(println (second groups)))

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