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Lists

Output

Join the elements of a list, separated by commas

Given the list [Apple, Banana, Carrot] produce "Apple, Banana, Carrot"

java

StringBuffer sb = new StringBuffer();
for (Iterator it = fruit.iterator(); it.hasNext();) {
sb.append(it.next());
if (it.hasNext()) {
sb.append(", ");
}
}
String result = sb.toString();

java 1.5 or later

StringBuilder sb = new StringBuilder(fruit.get(0));
for (String item : fruit.subList(1, fruit.size())) sb.append(", ").append(item);
String result = sb.toString();

java org.apache.commons

String result = StringUtils.join(fruit, ", ");

csharp .NET 3.5

using System.Collections.Generic;
public class JoinEach {
public static void Main() {
var list = new List<string>() {"Apple", "Banana", "Carrot"};
System.Console.WriteLine( string.Join(", ", list.ToArray()) );
}
}

cpp C++/CLI .NET 2.0

String^ result = String::Join(L", ", fruit->ToArray());

cpp boost

string fruits[] = {"Apple", "Banana", "Carrot"};
string result = boost::algorithm::join(fruits, ", ");

erlang

Result = string:join(Fruit, ", "),

erlang

Result = lists:foldl(fun (E, Acc) -> Acc ++ ", " ++ E end, hd(Fruit), tl(Fruit)),

erlang

Result = lists:flatten([ hd(Fruit) | [ ", " ++ X || X <- tl(Fruit)]]).

fsharp

let result = String.Join(", ", [|"Apple"; "Banana"; "Carrot"|])

fsharp

let result = (List.fold_left (fun acc item -> acc ^ (", " ^ item)) (List.hd fruit) (List.tl fruit))

fsharp

let result = (List.fold_left (fun (acc : StringBuilder) (item : string) -> acc.Append(", ").Append(item)) (new StringBuilder(List.hd fruit)) (List.tl fruit)).ToString()

fantom

["Apple", "Banana", "Carrot"].join(", ")

groovy

string = fruit.join(', ')

groovy

string = fruit.toString()[1..-2]

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