View Problem
Zero pad a number
Given the number 42, pad it to 8 characters like 00000042
perl
java
java 1.5 or later
clojure clojure
clojure clojure
clojure
cpp C++/CLI .NET 2.0
cpp C++/CLI .NET 2.0
cpp
cpp
cpp
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There are 26 other solutions in additional languages (csharp, erlang, fantom, fsharp ...)
sprintf("%08d", 42);
String formatted = new DecimalFormat("00000000").format(42);
String formatted = String.format("%08d", 42);
(defn pad
([x] (if (> 8 (.length (str x))) (pad (str 0 x)) (str x)))
)
([x] (if (> 8 (.length (str x))) (pad (str 0 x)) (str x)))
)
(defn pad [x]
(format "%08d" x))
(format "%08d" x))
(format "%08d" 42)
String^ formatted = Convert::ToString(42)->PadLeft(8, '0');
String^ formatted = String::Format("{0,8:D8}", 42);
std::printf("%08d", 42);
std::ostringstream os;
os << std::setw(8) << std::setfill('0') << 42 << std::ends;
std::cout << os.str() << std::endl;
os << std::setw(8) << std::setfill('0') << 42 << std::ends;
std::cout << os.str() << std::endl;
std::cout << boost::format("%|08|") % 42 << std::endl;
Submit a new solution for perl, java, clojure, or cpp
There are 26 other solutions in additional languages (csharp, erlang, fantom, fsharp ...)
