View Problem
Left Space pad a number
Given the number 73 left pad it to 10 characters 
perl
java
java 1.5 or later
csharp
Submit a new solution for perl, java, or csharp
There are 24 other solutions in additional languages (clojure, cpp, erlang, fantom ...)
" 73"
sprintf("%10d", 73);
private static String spaces(int spaces) {
StringBuffer sb = new StringBuffer();
for(int i=0; i<spaces; i++) {
sb.append(' ');
}
return sb.toString();
}
private static String leftPad(int number, int spaces) {
String numberString = String.valueOf(number);
return spaces(spaces - numberString.length()) + numberString;
}
StringBuffer sb = new StringBuffer();
for(int i=0; i<spaces; i++) {
sb.append(' ');
}
return sb.toString();
}
private static String leftPad(int number, int spaces) {
String numberString = String.valueOf(number);
return spaces(spaces - numberString.length()) + numberString;
}
String formatted = String.format("%10d", 73);
public class NumberLeftPadding {
public static void Main() {
string withStringDotFormat = string.Format("{0,10}", 73);
string withToStringDotPadLeft = 73.ToString().PadLeft(10);
}
}
public static void Main() {
string withStringDotFormat = string.Format("{0,10}", 73);
string withToStringDotPadLeft = 73.ToString().PadLeft(10);
}
}
Submit a new solution for perl, java, or csharp
There are 24 other solutions in additional languages (clojure, cpp, erlang, fantom ...)
