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Display the unique items in a list
Display the unique items in a list, e.g. given ages =
perl
perl
perl
perl
perl
java
groovy
groovy
Submit a new solution for perl, java, or groovy
There are 17 other solutions in additional languages (clojure, cpp, csharp, erlang ...)
[18, 16, 17, 18, 16, 19, 14, 17, 19, 18], display the unique elements, i.e. with duplicates removed.
@ages = (18, 16, 17, 18, 16, 19, 14, 17, 19, 18);
@seen{@ages} = ();
@unique = keys %seen;
print join(', ', @unique);
@seen{@ages} = ();
@unique = keys %seen;
print join(', ', @unique);
@ages = (18, 16, 17, 18, 16, 19, 14, 17, 19, 18);
@unique = grep(!$seen{$_}++, @ages);
print join(', ', @unique);
@unique = grep(!$seen{$_}++, @ages);
print join(', ', @unique);
@ages = (18, 16, 17, 18, 16, 19, 14, 17, 19, 18);
print join(', ', grep(!$seen{$_}++, @ages));
print join(', ', grep(!$seen{$_}++, @ages));
@ages = (18, 16, 17, 18, 16, 19, 14, 17, 19, 18);
for (@ages) {
push(@unique, $_) unless $seen{$_}++;
}
print join(', ', @unique);
for (@ages) {
push(@unique, $_) unless $seen{$_}++;
}
print join(', ', @unique);
use List::MoreUtils qw(uniq);
@ages = (18, 16, 17, 18, 16, 19, 14, 17, 19, 18);
print join(', ', uniq(@ages));
@ages = (18, 16, 17, 18, 16, 19, 14, 17, 19, 18);
print join(', ', uniq(@ages));
Set<Integer> ages = new TreeSet<Integer>(Arrays.asList(new Integer[]{18, 16, 17, 18, 16, 19, 14, 17, 19, 18}));
System.out.println(ages);
System.out.println(ages);
ages = [18, 16, 17, 18, 16, 19, 14, 17, 19, 18]
println ages.unique()
println ages.unique()
ages = [18, 16, 17, 18, 16, 19, 14, 17, 19, 18]
unique = ages as Set
println unique
unique = ages as Set
println unique
Submit a new solution for perl, java, or groovy
There are 17 other solutions in additional languages (clojure, cpp, csharp, erlang ...)
