View Problem
Perform an action a fixed number of times with a counter
Display the string 
php
erlang
erlang
csharp
fsharp
fsharp
fantom
fantom
Submit a new solution for php, erlang, csharp, fsharp ...
There are 14 other solutions in additional languages (clojure, cpp, groovy, haskell ...)
"10 .. 9 .. 8 .. 7 .. 6 .. 5 .. 4 .. 3 .. 2 .. 1 .. Liftoff!"
for($i = 10; $i > 0; $i--) {
echo $i." .. ";
}
echo "Liftoff!";
echo $i." .. ";
}
echo "Liftoff!";
fromto(10, 1, -1, fun (X) -> io:format("~B .. ", [X]) end), io:format("Liftoff!~n").
lists:foreach(fun (X) -> io:format("~B .. ", [X]) end, lists:seq(10, 1, -1)), io:format("Liftoff!~n").
for (int i = 10; i > 0; i--)
{
Console.Write("{0} .. ", i);
}
Console.WriteLine("Liftoff!");
{
Console.Write("{0} .. ", i);
}
Console.WriteLine("Liftoff!");
for i = 10 downto 1 do printf "%d .. " i done
printfn "Liftoff!"
printfn "Liftoff!"
// Repetition via ranging over a Sequence type
for i in {10 .. -1 .. 1} do printf "%d .. " i done ; printfn "Liftoff!"
for i in {10 .. -1 .. 1} do printf "%d .. " i done ; printfn "Liftoff!"
(10..1).each { Env.cur.out.print("$it .. ") }
Env.cur.out.print("Liftoff!")
Env.cur.out.print("Liftoff!")
for (i := 10; i >= 1; i--)
Env.cur.out.print("$i .. ")
Env.cur.out.print("Liftoff!")
Env.cur.out.print("$i .. ")
Env.cur.out.print("Liftoff!")
Submit a new solution for php, erlang, csharp, fsharp ...
There are 14 other solutions in additional languages (clojure, cpp, groovy, haskell ...)
