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Rotate a list
Given a list 
python
python
clojure
erlang
erlang
cpp C++/CLI .NET 2.0
cpp
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There are 16 other solutions in additional languages (csharp, fantom, fsharp, groovy ...)
["apple", "orange", "grapes", "bananas"], rotate it by removing the first item and placing it on the end to yield ["orange", "grapes", "bananas", "apple"]
l = ["apple", "orange", "grapes", "bananas"]
first, l = l[0], l[1:] + l[:1]
first, l = l[0], l[1:] + l[:1]
fruit = ['apple', 'orange', 'grapes', 'bananas']
fruit.append(fruit.pop(0))
fruit.append(fruit.pop(0))
(let [fruit ["apple" "orange" "grapes" "bananas"]]
(concat (rest fruit) [(first fruit)])
(concat (rest fruit) [(first fruit)])
N = 1, {Left, Right} = lists:split(N, List), Result = Right ++ Left,
N = 1, Result = rotate(N, List),
fruit->Add(fruit[0]); fruit->RemoveAt(0);
rotate(fruit.begin(), fruit.begin()+1, fruit.end());
Submit a new solution for python, clojure, erlang, or cpp
There are 16 other solutions in additional languages (csharp, fantom, fsharp, groovy ...)
