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Rotate a list
Given a list 
python
python
clojure
erlang
erlang
fsharp
Submit a new solution for python, clojure, erlang, or fsharp
There are 17 other solutions in additional languages (cpp, csharp, fantom, groovy ...)
["apple", "orange", "grapes", "bananas"], rotate it by removing the first item and placing it on the end to yield ["orange", "grapes", "bananas", "apple"]
l = ["apple", "orange", "grapes", "bananas"]
first, l = l[0], l[1:] + l[:1]
first, l = l[0], l[1:] + l[:1]
fruit = ['apple', 'orange', 'grapes', 'bananas']
fruit.append(fruit.pop(0))
fruit.append(fruit.pop(0))
(let [fruit ["apple" "orange" "grapes" "bananas"]]
(concat (rest fruit) [(first fruit)])
(concat (rest fruit) [(first fruit)])
N = 1, {Left, Right} = lists:split(N, List), Result = Right ++ Left,
N = 1, Result = rotate(N, List),
let rotate list n =
if n <= 0 then
list
else
let (left, right) = split_at list (n - 1)
right @ left
// ------
let result = (rotate fruit 1)
if n <= 0 then
list
else
let (left, right) = split_at list (n - 1)
right @ left
// ------
let result = (rotate fruit 1)
Submit a new solution for python, clojure, erlang, or fsharp
There are 17 other solutions in additional languages (cpp, csharp, fantom, groovy ...)
