View Problem
Zero pad a number
Given the number 42, pad it to 8 characters like 00000042
python
clojure clojure
clojure clojure
clojure
fsharp
fsharp
fsharp
fsharp
fsharp
fantom
fantom
erlang
erlang
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There are 24 other solutions in additional languages (cpp, csharp, go, groovy ...)
"%08d" % 42
(defn pad
([x] (if (> 8 (.length (str x))) (pad (str 0 x)) (str x)))
)
([x] (if (> 8 (.length (str x))) (pad (str 0 x)) (str x)))
)
(defn pad [x]
(format "%08d" x))
(format "%08d" x))
(format "%08d" 42)
printfn "%08d" 42
let formatted = sprintf "%08d" 42
printfn "%s" formatted
printfn "%s" formatted
let buffer = new StringBuilder()
Printf.bprintf buffer "%08d" 42
printfn "%s" (buffer.ToString())
Printf.bprintf buffer "%08d" 42
printfn "%s" (buffer.ToString())
let formatted = String.Format("{0,8:D8}", 42)
Console.WriteLine(formatted)
Console.WriteLine(formatted)
let formatted = Convert.ToString(42).PadLeft(8, '0')
Console.WriteLine(formatted)
Console.WriteLine(formatted)
formatted := 42.toStr.padl(8, '0')
formatted := 42.toLocale("00000000")
Formatted = io_lib:format("~8..0B", [42]),
io:format("~8..0B~n", [42]).
Submit a new solution for python, clojure, fsharp, fantom ...
There are 24 other solutions in additional languages (cpp, csharp, go, groovy ...)
