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Check if a string matches with groups

Display "two" if "one two three" matches /one (.*) three/
DiskEdit
python
match = re.match(r'one (.*) three', 'one two three')
if match:
print match.group(1)
DiskEdit
clojure
(if-let [groups (re-matches #"one (.*) three" "one two three")]
(println (second groups)))
ExpandDiskEdit
fsharp
let regmatch = (Regex.Match("one two three", "one (.*) three"))
if regmatch.Success then (printfn "%s" (regmatch.Groups.[1].Captures.[0].ToString()))
ExpandDiskEdit
fantom
m := Regex<|one (.*) three|>.matcher("one two three")
if (m.matches)
echo("${m.group(1)}")
ExpandDiskEdit
java
Pattern pattern = Pattern.compile("one (.*) three");
Matcher matcher = pattern.matcher("one two three");
if (matcher.matches()) {
System.out.println(matcher.group(1));
}
DiskEdit
csharp
using System;
using System.Text.RegularExpressions;

public class RegexBackReference {
public static void Main() {
var oneTwoThree = "one two three";
var pattern = "one (.*) three";

Match match = Regex.Match(oneTwoThree, pattern);

// group 0 is the entire match. 1 is the first backreference
Console.WriteLine(match.Groups[1]);
}
}

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