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Display the unique items in a list
Display the unique items in a list, e.g. given ages =
python 2.5.2
csharp .NET 3.5
java
Submit a new solution for python, csharp, or java
There are 22 other solutions in additional languages (clojure, cpp, erlang, fantom ...)
[18, 16, 17, 18, 16, 19, 14, 17, 19, 18], display the unique elements, i.e. with duplicates removed.
ages = [18, 16, 17, 18, 16, 19, 14, 17, 19, 18]
unique_ages = list(set(ages))
unique_ages = list(set(ages))
using System.Collections.Generic;
using System.Linq;
public class UniqueElements {
public static void Main() {
var list = new List<int>() { 18, 16, 17, 18, 16, 19, 14, 17, 19, 18 };
var uniques = list.Distinct();
}
}
using System.Linq;
public class UniqueElements {
public static void Main() {
var list = new List<int>() { 18, 16, 17, 18, 16, 19, 14, 17, 19, 18 };
var uniques = list.Distinct();
}
}
Set<Integer> ages = new TreeSet<Integer>(Arrays.asList(new Integer[]{18, 16, 17, 18, 16, 19, 14, 17, 19, 18}));
System.out.println(ages);
System.out.println(ages);
Submit a new solution for python, csharp, or java
There are 22 other solutions in additional languages (clojure, cpp, erlang, fantom ...)
