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Check if a string matches a regular expression
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python
fsharp
fantom
groovy
groovy 1.6.1+
groovy 1.6.1+
groovy 1.6.1+
groovy
haskell
Submit a new solution for python, fsharp, fantom, groovy ...
There are 16 other solutions in additional languages (clojure, cpp, csharp, erlang ...)
"ok" if "Hello" matches /[A-Z][a-z]+/
found = re.match(r'[A-Z][a-z]+', 'Hello')
if found:
print 'ok'
if found:
print 'ok'
if (Regex.IsMatch("Hello", "[A-Z][a-z]+")) then printfn "ok"
if (Regex<|[A-Z][a-z]+|>.matches("Hello"))
echo("ok")
echo("ok")
if ("Hello" =~ /[A-Z][a-z]+/) println 'ok'
if ("Hello".find(/[A-Z][a-z]+/)) println 'ok'
// with precompiled regex
def regex = ~/[A-Z][a-z]+/
if ("Hello".find(regex)) println 'ok'
def regex = ~/[A-Z][a-z]+/
if ("Hello".find(regex)) println 'ok'
// with precompiled regex
def regex = ~/[A-Z][a-z]+/
if ("Hello".matches(regex)) println 'ok'
def regex = ~/[A-Z][a-z]+/
if ("Hello".matches(regex)) println 'ok'
if ("Hello".matches("[A-Z][a-z]+")) println 'ok'
import Text.Regex.Posix
main = if "Hello" =~ "[A-Z][a-z]+" then putStrLn "OK" else return ()
main = if "Hello" =~ "[A-Z][a-z]+" then putStrLn "OK" else return ()
Submit a new solution for python, fsharp, fantom, groovy ...
There are 16 other solutions in additional languages (clojure, cpp, csharp, erlang ...)
