View Problem
Process each file in a directory recursively
import os
results = (process(os.path.join(p, n)) for p,d,l in os.walk(".") for n in l)
results = (process(os.path.join(p, n)) for p,d,l in os.walk(".") for n in l)
def procdir(dirname)
Dir.foreach(dirname) do |dir|
dirpath = dirname + '/' + dir
if File.directory?(dirpath) then
if dir != '.' && dir != '..' then
puts "DIRECTORY: #{dirpath}" ; procdir(dirpath)
end
else
puts "FILE: #{dirpath}"
end
end
end
# ------
procdir('/tmp')
Dir.foreach(dirname) do |dir|
dirpath = dirname + '/' + dir
if File.directory?(dirpath) then
if dir != '.' && dir != '..' then
puts "DIRECTORY: #{dirpath}" ; procdir(dirpath)
end
else
puts "FILE: #{dirpath}"
end
end
end
# ------
procdir('/tmp')
processDirectory(new File("c:\\"));
if ($dir_handle = opendir($dir))
list_dir($dir_handle);
function list_dir($dh) {
// as long as we can read the dir
while (($file = readdir($dh)) !== false) {
// if it's a dir and it's not the current dir nor the above dir
if (is_dir($file) && $file != '.' && $file !='..') {
// open the dir, print it's name and all files inside
$handle = opendir($file);
echo $file."\n";
list_dir($handle);
// if it's a simple file
} else if ($file != '.' && $file !='..') {
// type it's name
echo $file."\n";
}
}
closedir($dir_handle); // close the dirs
}
Submit a new solution for python, ruby, java, or php
There are 7 other solutions in additional languages (cpp, erlang, fsharp, groovy ...)
