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Parse a date and time from a string

Given the string "2008-05-06 13:29", parse it as a date representing 6th March, 2008 1:29:00pm in the local time zone.
import time
time.strptime("2008-05-06 13:29", "%Y-%m-%d %H:%M")

Display information about a date

Display the day of month, day of year, month name and day name of the day 8 days from now.
from datetime import datetime, timedelta

eightDaysFromNow = + timedelta(days=8)

print eightDaysFromNow.strftime('%d') # day of month
print eightDaysFromNow.strftime('%j') # day of year
print eightDaysFromNow.strftime('%B') # month name FULL
print eightDaysFromNow.strftime('%A') # day of week name FULL

Display a date in different locales

Display a language/locale friendly version of New Year's Day for 2009 for several languages/locales. E.g. for languages English, French, German, Italian, Dutch the output might be something like:

Thursday, January 1, 2009
jeudi 1 janvier 2009
giovedì 1 gennaio 2009
Donnerstag, 1. Januar 2009
donderdag 1 januari 2009

(Indicate in comments where possible if any language specific or operating system configuration needs to be in place.)
from datetime import datetime
from locale import setlocale, LC_TIME

now = datetime(2009, 1, 1)

locales = ('en_us', 'fr_fr', 'it_it', 'de_de', 'nl_nl')
for locale in locales:
setlocale(LC_TIME, locale)
print now.strftime('%A, %B %d %Y')

Display the current date and time

Create a Date object representing the current date and time. Print it out.
If you can also do this without creating a Date object you can show that too.
from datetime import datetime
print datetime.utcnow()