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Fetch an element of a list by index

Given the list [One, Two, Three, Four, Five], fetch the third element ('Three')
ruby
list = ['One', 'Two', 'Three', 'Four', 'Five']
list[2]
['One', 'Two', 'Three', 'Four', 'Five'].fetch(2)
list = ['One', 'Two', 'Three', 'Four', 'Five']
list.at(2)
['One', 'Two', 'Three', 'Four', 'Five'][2] # <= note the [2] at end of array
clojure
(nth '[One Two Three Four Five] 2)
erlang
Result = lists:nth(3, List),
Result = element(3, list_to_tuple(List)),
{Left, _} = lists:split(3, List), Result = lists:last(Left),
Result = nth0(2, List),
fsharp
let result = List.nth ["One"; "Two"; "Three"; "Four"; "Five"] 2

Fetch the last element of a list

Given the list [Red, Green, Blue], access the last element ('Blue')
ruby
['Red', 'Green', 'Blue'][-1]
['Red', 'Green', 'Blue'].at(-1)
['Red', 'Green', 'Blue'].last
['Red', 'Green', 'Blue'].fetch(-1)
clojure
(last '[One Two Three Four Five])
erlang
Result = lists:last(List),
Result = last(List),
Result = hd(lists:reverse(List)),
Result = lists:nth(length(List), List),
fsharp
let last list =
let rec last' list' =
match list' with
| [x] -> x
| x :: xs -> last' xs
if List.is_empty list then failwith "empty list" else last' list

// ------

let result = last list
let result = (List.nth list ((List.length list) - 1))
let result = (List.hd (List.rev list))

Find the common items in two lists

Given two lists, find the common items. E.g. given beans = ['broad', 'mung', 'black', 'red', 'white'] and colors = ['black', 'red', 'blue', 'green'], what are the bean varieties that are also color names?
ruby
common = (beans.intersection(colors)).to_a
clojure
(use 'clojure.set)

(let [beans '[broad mung black red white]
colors '[black red blue green]]
(intersection (set beans) (set colors)))
erlang
Beans = sets:from_list([broad, mung, black, red, white]), Colors = sets:from_list([black, red, blue, green]),

Common = sets:to_list(sets:intersection(Beans, Colors)),
fsharp
let beans = (Set.of_list ["broad"; "mung"; "black"; "red"; "white"])
let colors = (Set.of_list ["black"; "red"; "blue"; "green"])
let common = (Set.intersect beans colors)
let beans = Set ["broad"; "mung"; "black"; "red"; "white"]
let colors = Set ["black"; "red"; "blue"; "green"]
let common = Set.intersect beans colors
// Iterates elements of
// list1 across Elements of list2 returning a list of string options
// as generated by List.tryFind
let findCommon(list1 : 'a list, list2 : 'a list) : 'a list =
list1 |> List.map(fun y -> list2 |> List.tryFind(fun x -> y = x))
// Iterates elements of string option list generated above
// returning a string list containing common elements of List1 and List2
|> List.fold(fun acc x -> if x <> None then x.Value::acc else acc) []
// reverse order of list (can't seem to make List.foldBack work for this
|> List.rev

let beans = ["broad"; "mung"; "black"; "red"; "white"]
let colors = ["black"; "red"; "blue"; "green"]
printfn "%A" (findCommon(beans, colors)) ;;

Display the unique items in a list

Display the unique items in a list, e.g. given ages = [18, 16, 17, 18, 16, 19, 14, 17, 19, 18], display the unique elements, i.e. with duplicates removed.
ruby
ages = [18, 16, 17, 18, 16, 19, 14, 17, 19, 18]
p ages.uniq
ages = [18, 16, 17, 18, 16, 19, 14, 17, 19, 18]
ages.uniq!
p ages
ages = (Set.new [18, 16, 17, 18, 16, 19, 14, 17, 19, 18]).to_a
p ages
clojure
;; returns a set
(set [18, 16, 17, 18, 16, 19, 14, 17, 19, 18])
;;#{14 16 17 18 19}

;; returns a lazy sequence of the unique elements
(distinct [18, 16, 17, 18, 16, 19, 14, 17, 19, 18])
;;(18 16 17 19 14)


erlang
Ages = sets:to_list(sets:from_list([18, 16, 17, 18, 16, 19, 14, 17, 19, 18])), io:format("~w~n", [Ages]).
lists:usort([18, 16, 17, 18, 16, 19, 14, 17, 19, 18]).
fsharp
(Set.ofList [18; 16; 17; 18; 16; 19; 14; 17; 19; 18]) |> Set.iter (fun age -> printf "%d, " age)