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Display the unique items in a list
Display the unique items in a list, e.g. given ages =
ruby
ruby
ruby
clojure 1.0.0
erlang
erlang
Submit a new solution for ruby, clojure, or erlang
There are 19 other solutions in additional languages (cpp, csharp, fantom, fsharp ...)
[18, 16, 17, 18, 16, 19, 14, 17, 19, 18], display the unique elements, i.e. with duplicates removed.
ages = [18, 16, 17, 18, 16, 19, 14, 17, 19, 18]
p ages.uniq
p ages.uniq
ages = [18, 16, 17, 18, 16, 19, 14, 17, 19, 18]
ages.uniq!
p ages
ages.uniq!
p ages
ages = (Set.new [18, 16, 17, 18, 16, 19, 14, 17, 19, 18]).to_a
p ages
p ages
;; returns a set
(set [18, 16, 17, 18, 16, 19, 14, 17, 19, 18])
;;#{14 16 17 18 19}
;; returns a lazy sequence of the unique elements
(distinct [18, 16, 17, 18, 16, 19, 14, 17, 19, 18])
;;(18 16 17 19 14)
(set [18, 16, 17, 18, 16, 19, 14, 17, 19, 18])
;;#{14 16 17 18 19}
;; returns a lazy sequence of the unique elements
(distinct [18, 16, 17, 18, 16, 19, 14, 17, 19, 18])
;;(18 16 17 19 14)
Ages = sets:to_list(sets:from_list([18, 16, 17, 18, 16, 19, 14, 17, 19, 18])), io:format("~w~n", [Ages]).
lists:usort([18, 16, 17, 18, 16, 19, 14, 17, 19, 18]).
Submit a new solution for ruby, clojure, or erlang
There are 19 other solutions in additional languages (cpp, csharp, fantom, fsharp ...)
