View Problem
Create a histogram map from a list
Given the list 
ruby
ruby 1.9
ruby
clojure
clojure
clojure
clojure
clojure
Submit a new solution for ruby or clojure
There are 31 other solutions in additional languages (cpp, csharp, erlang, fantom ...)
[a,b,a,c,b,b], produce a map {a:2, b:3, c:1} which contains the count of each unique item in the list
histogram = {}
list.each { |item| histogram[item] = (histogram[item] || 0) +1 }
list.each { |item| histogram[item] = (histogram[item] || 0) +1 }
list = %w{a b a c b b}
histogram = list.each_with_object(Hash.new(0)) do |item, hash|
hash[item] += 1
end
p histogram # => {"a"=>2, "b"=>3, "c"=>1}
histogram = list.each_with_object(Hash.new(0)) do |item, hash|
hash[item] += 1
end
p histogram # => {"a"=>2, "b"=>3, "c"=>1}
list.inject(Hash.new(0)) {|h, item| h[item] += 1; h}
(let [l '[a b a c b b]]
(loop [m {}
d (distinct l)]
(let [item (first d)]
(if (zero? (count d))
m
(recur
(assoc m
item
(count
(filter #(= item %) l)))
(rest d))))))
(loop [m {}
d (distinct l)]
(let [item (first d)]
(if (zero? (count d))
m
(recur
(assoc m
item
(count
(filter #(= item %) l)))
(rest d))))))
(->> [:a :b :a :c :b :b]
(group-by identity)
(reduce (fn [m e] (assoc m (first e) (count (second e)))) {}))
(group-by identity)
(reduce (fn [m e] (assoc m (first e) (count (second e)))) {}))
(reduce conj {} (for [[x xs] (group-by identity "abacbb")] [x (count xs)]))
(frequencies ["a","b","a","c","b","b"])
(frequencies '[a b a c b b])
Submit a new solution for ruby or clojure
There are 31 other solutions in additional languages (cpp, csharp, erlang, fantom ...)
