View Problem
Zero pad a number
Given the number 42, pad it to 8 characters like 00000042
ruby
ruby
cpp C++/CLI .NET 2.0
cpp C++/CLI .NET 2.0
cpp
cpp
cpp
clojure clojure
clojure clojure
clojure
fsharp
fsharp
fsharp
fsharp
fsharp
Submit a new solution for ruby, cpp, clojure, or fsharp
There are 22 other solutions in additional languages (csharp, erlang, fantom, go ...)
42.to_s.rjust(8,"0")
"%08d" % 42
String^ formatted = Convert::ToString(42)->PadLeft(8, '0');
String^ formatted = String::Format("{0,8:D8}", 42);
std::printf("%08d", 42);
std::ostringstream os;
os << std::setw(8) << std::setfill('0') << 42 << std::ends;
std::cout << os.str() << std::endl;
os << std::setw(8) << std::setfill('0') << 42 << std::ends;
std::cout << os.str() << std::endl;
std::cout << boost::format("%|08|") % 42 << std::endl;
(defn pad
([x] (if (> 8 (.length (str x))) (pad (str 0 x)) (str x)))
)
([x] (if (> 8 (.length (str x))) (pad (str 0 x)) (str x)))
)
(defn pad [x]
(format "%08d" x))
(format "%08d" x))
(format "%08d" 42)
printfn "%08d" 42
let formatted = sprintf "%08d" 42
printfn "%s" formatted
printfn "%s" formatted
let buffer = new StringBuilder()
Printf.bprintf buffer "%08d" 42
printfn "%s" (buffer.ToString())
Printf.bprintf buffer "%08d" 42
printfn "%s" (buffer.ToString())
let formatted = String.Format("{0,8:D8}", 42)
Console.WriteLine(formatted)
Console.WriteLine(formatted)
let formatted = Convert.ToString(42).PadLeft(8, '0')
Console.WriteLine(formatted)
Console.WriteLine(formatted)
Submit a new solution for ruby, cpp, clojure, or fsharp
There are 22 other solutions in additional languages (csharp, erlang, fantom, go ...)
