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Fetch the last element of a list
Given the list 
ruby
ruby
ruby
ruby
cpp C++/CLI .NET 2.0
cpp
fsharp
fsharp
fsharp
clojure
Submit a new solution for ruby, cpp, fsharp, or clojure
There are 21 other solutions in additional languages (csharp, erlang, fantom, groovy ...)
[Red, Green, Blue], access the last element ('Blue')
['Red', 'Green', 'Blue'][-1]
['Red', 'Green', 'Blue'].at(-1)
['Red', 'Green', 'Blue'].last
['Red', 'Green', 'Blue'].fetch(-1)
String^ result = list[list->Count - 1];
string last_elem = lst.back();
let last list =
let rec last' list' =
match list' with
| [x] -> x
| x :: xs -> last' xs
if List.is_empty list then failwith "empty list" else last' list
// ------
let result = last list
let rec last' list' =
match list' with
| [x] -> x
| x :: xs -> last' xs
if List.is_empty list then failwith "empty list" else last' list
// ------
let result = last list
let result = (List.nth list ((List.length list) - 1))
let result = (List.hd (List.rev list))
(last '[One Two Three Four Five])
Submit a new solution for ruby, cpp, fsharp, or clojure
There are 21 other solutions in additional languages (csharp, erlang, fantom, groovy ...)
