View Problem

Perform an action multiple times based on a boolean condition, checked before the first action (WHILE .. DO)

Starting with a variable x=1, Print the sequence "1,2,4,8,16,32,64,128," by doubling x and checking that x is less than 150.
DiskEdit
ruby
x=1
while x < 150
puts x
x <<= 1
end
ExpandDiskEdit
cpp C++/CLI .NET 2.0
int x = 1;

while (x < 150) { x *= 2; Console::Write("{0},", x); }
Console::WriteLine();
ExpandDiskEdit
cpp
for (int x = 1; x < 150; x *= 2) { std::cout << x << ","; }
std::cout << std::endl;
ExpandDiskEdit
fsharp
let mutable x = 1
while x < 150 do printf "%d, " x ; (x <- x * 2) done
DiskEdit
fsharp
// The problem is clearly geared towards imperative languages ;-)
// No need to mutate any variable, here's how to do it loop-free functional:
let rec powers2 i = seq { if i < 150 then yield i; yield! powers2 (i*2) }
powers2 1 |> Seq.iter (fun i -> printf "%i, " i)
ExpandDiskEdit
erlang
X = 1, print_while_X_less_150(X).
ExpandDiskEdit
erlang
Pred = fun (X) -> X < 150 end,
Action = fun (X) -> io:format("~B,", [X]), X * 2 end,
X = 1,

while_do(Pred, Action, X).
DiskEdit
csharp
int x = 1;

while (x < 150)
{
x *= 2;
Console.Write("{0},", x);
}
DiskEdit
haskell
main :: IO ()
main = loop 1
where
loop x | x < 150 = do
putStr (show x ++ ",")
loop (x * 2)
loop _ = return ()
DiskEdit
haskell
main = mapM_ print $ takeWhile (<150) $ iterate (* 2) 1

Submit a new solution for ruby, cpp, fsharp, erlang ...
There are 10 other solutions in additional languages (clojure, fantom, groovy, java ...)