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Subdivide A Problem To A Pool Of Workers (No Shared Data)
Take a hard to compute problem and split it up between multiple worker threads. In your solution, try to fully utilize available cores or processors. (I'm looking at you, Python!)
Note: In this question, there should be no need for shared state between worker threads while the problem is being solved. Only after every thread completes computation are the answers recombined into a single output.
Example:
-Input-
(In python syntax)
In other words, a list of random strings.
-Output-
(In python syntax)
In other words, all possible permutations of each input string are computed.
Note: In this question, there should be no need for shared state between worker threads while the problem is being solved. Only after every thread completes computation are the answers recombined into a single output.
Example:
-Input-
(In python syntax)
["ab", "we", "tfe", "aoj"]
In other words, a list of random strings.
-Output-
(In python syntax)
[ ["ab", "ba", "aa", "bb", "a", "b"], ["we", "ew", "ww", "ee", "w", "e"], ...
In other words, all possible permutations of each input string are computed.
ruby
array, threads, answers = ["ab", "we", "tfe", "aoj"], [], []
array.each { |word|
threads << Thread.new(word.split '' ) do |x|
answer = []
x.each { |a|
answer << a
x.each { |b| answer << [a, b].join }
}
answers << answer
end
}
threads.each {|thr| thr.join}
answers
array.each { |word|
threads << Thread.new(word.split '' ) do |x|
answer = []
x.each { |a|
answer << a
x.each { |b| answer << [a, b].join }
}
answers << answer
end
}
threads.each {|thr| thr.join}
answers
cpp
vector<string> input;
input.push_back("ab");
input.push_back("we");
input.push_back("tfe");
input.push_back("aoj");
// Make the capacity for 'output' the same as 'input'
vector<set<string> > output(input.size());
#pragma omp parallel for
for (int i = 0; i < input.size(); ++i) {
set<string> perms;
generate_perms(input[i], perms);
#pragma omp critical
// Must use operator[]() and not push_back() since this line
// might be called in any order with respect to 'i'
output[i] = perms;
}
cout << output << endl;
input.push_back("ab");
input.push_back("we");
input.push_back("tfe");
input.push_back("aoj");
// Make the capacity for 'output' the same as 'input'
vector<set<string> > output(input.size());
#pragma omp parallel for
for (int i = 0; i < input.size(); ++i) {
set<string> perms;
generate_perms(input[i], perms);
#pragma omp critical
// Must use operator[]() and not push_back() since this line
// might be called in any order with respect to 'i'
output[i] = perms;
}
cout << output << endl;
fsharp
open System
let input = [| "ab"; "we"; "tfe"; "aoj" |]
/// Computes all permutations of an array
let rec permute = function
| [| |] -> [| [| |] |]
| a ->
a
|> Array.mapi (fun i ai ->
// Take all elements in the array apart from the i.th, compute
// their permutations, then attach element i at the front of each perm
Array.sub a 0 i
|> Array.append (Array.sub a (i + 1) (a.Length - i - 1))
|> permute
|> Array.map (fun perm -> Array.append [| ai |] perm)
)
|> Array.concat
/// Computes all permutations of a string
let permuteString (s: string) =
s.ToCharArray()
|> permute
|> Array.map (fun p -> new String(p))
let output =
input
|> Array.map (fun word -> async { return (permuteString word) })
|> Async.Parallel
|> Async.RunSynchronously
let input = [| "ab"; "we"; "tfe"; "aoj" |]
/// Computes all permutations of an array
let rec permute = function
| [| |] -> [| [| |] |]
| a ->
a
|> Array.mapi (fun i ai ->
// Take all elements in the array apart from the i.th, compute
// their permutations, then attach element i at the front of each perm
Array.sub a 0 i
|> Array.append (Array.sub a (i + 1) (a.Length - i - 1))
|> permute
|> Array.map (fun perm -> Array.append [| ai |] perm)
)
|> Array.concat
/// Computes all permutations of a string
let permuteString (s: string) =
s.ToCharArray()
|> permute
|> Array.map (fun p -> new String(p))
let output =
input
|> Array.map (fun word -> async { return (permuteString word) })
|> Async.Parallel
|> Async.RunSynchronously
// like the Java and Groovy solutions, does not duplicate letters
open System
open System.Threading.Tasks
let input = [| "ab"; "we"; "tfe"; "aoj" |]
let factorial n =
seq { 1 .. n } |> Seq.reduce (*)
let swap (arr:'a[]) i j =
[| for k = 0 to arr.Length - 1 do
yield if k = i then arr.[j] elif k = j then arr.[i] else arr.[k] |]
let rec permutation (k:int,j:int) (r:'a[]) =
if j = (r.Length + 1) then r
else permutation (k/j+1, j+1) (swap r (j-1) (k%j))
let permutations (source:'a[]) = seq {
for k = 0 to (factorial source.Length) - 1 do
yield permutation (k,2) source
}
let permute (word:string) =
let letters = word.ToCharArray()
permutations letters
|> Seq.map (fun chars -> String(chars))
|> Array.ofSeq
let tasks =
input |> Array.map (fun word -> Task.Factory.StartNew(fun () -> permute word))
let taskResult (t:Task<_>) =
t.Result
let output = Task.Factory.ContinueWhenAll(tasks, fun ts -> Array.map taskResult ts).Result
open System
open System.Threading.Tasks
let input = [| "ab"; "we"; "tfe"; "aoj" |]
let factorial n =
seq { 1 .. n } |> Seq.reduce (*)
let swap (arr:'a[]) i j =
[| for k = 0 to arr.Length - 1 do
yield if k = i then arr.[j] elif k = j then arr.[i] else arr.[k] |]
let rec permutation (k:int,j:int) (r:'a[]) =
if j = (r.Length + 1) then r
else permutation (k/j+1, j+1) (swap r (j-1) (k%j))
let permutations (source:'a[]) = seq {
for k = 0 to (factorial source.Length) - 1 do
yield permutation (k,2) source
}
let permute (word:string) =
let letters = word.ToCharArray()
permutations letters
|> Seq.map (fun chars -> String(chars))
|> Array.ofSeq
let tasks =
input |> Array.map (fun word -> Task.Factory.StartNew(fun () -> permute word))
let taskResult (t:Task<_>) =
t.Result
let output = Task.Factory.ContinueWhenAll(tasks, fun ts -> Array.map taskResult ts).Result
groovy
// as per Java answer, doesn't duplicate chars from input string, i.e. no 'aa'
def ans = [].asSynchronized()
def words = ["ab", "we", "tfe", "aoj"]
def threads = []
void permutations(String prefix, String w, Set<String> permSet) {
int n = w.size()
if (!n) permSet << prefix
else n.times { i ->
permutations(prefix + w[i], w[0..<i] + w[i+1..<n], permSet)
}
}
words.each { word ->
def t = Thread.start {
def wordAns = [] as Set
for (int i = 0; i < word.size(); i++)
for (int j = i + 1; j <= word.size(); j++)
permutations("", word[i..<j], wordAns)
ans << wordAns
}
threads << t
}
threads.each{ it.join() }
println ans
def ans = [].asSynchronized()
def words = ["ab", "we", "tfe", "aoj"]
def threads = []
void permutations(String prefix, String w, Set<String> permSet) {
int n = w.size()
if (!n) permSet << prefix
else n.times { i ->
permutations(prefix + w[i], w[0..<i] + w[i+1..<n], permSet)
}
}
words.each { word ->
def t = Thread.start {
def wordAns = [] as Set
for (int i = 0; i < word.size(); i++)
for (int j = i + 1; j <= word.size(); j++)
permutations("", word[i..<j], wordAns)
ans << wordAns
}
threads << t
}
threads.each{ it.join() }
println ans
// as per Java answer, doesn't duplicate chars from input string, i.e. no 'aa'
def ans = [].asSynchronized()
def words = ["ab", "we", "tfe", "aoj"]
void permutations(String prefix, String w, Set<String> permSet) {
int n = w.size()
if (!n) permSet << prefix
else n.times { i ->
permutations(prefix + w[i], w[0..<i] + w[i+1..<n], permSet)
}
}
withParallelizer {
words.eachParallel { word ->
def wordAns = [] as Set
for (int i = 0; i < word.size(); i++)
for (int j = i + 1; j <= word.size(); j++)
permutations("", word[i..<j], wordAns)
ans << wordAns
}
}
println ans
def ans = [].asSynchronized()
def words = ["ab", "we", "tfe", "aoj"]
void permutations(String prefix, String w, Set<String> permSet) {
int n = w.size()
if (!n) permSet << prefix
else n.times { i ->
permutations(prefix + w[i], w[0..<i] + w[i+1..<n], permSet)
}
}
withParallelizer {
words.eachParallel { word ->
def wordAns = [] as Set
for (int i = 0; i < word.size(); i++)
for (int j = i + 1; j <= word.size(); j++)
permutations("", word[i..<j], wordAns)
ans << wordAns
}
}
println ans
Subdivide A Problem To A Pool Of Workers (Shared Data)
Take a hard to compute problem and split it up between multiple worker threads. In your solution, try to fully utilize available cores or processors. (I'm looking at you, Python!)
Note: In this question, there should be a need for shared state between worker threads while the problem is being solved.
Example:
-Conway Game of Life-
From Wikipedia:
The universe of the Game of Life is an infinite two-dimensional orthogonal grid of square cells, each of which is in one of two possible states, live or dead. Every cell interacts with its eight neighbors, which are the cells that are directly horizontally, vertically, or diagonally adjacent. At each step in time, the following transitions occur:
1. Any live cell with fewer than two live neighbours dies, as if caused by underpopulation.
2. Any live cell with more than three live neighbours dies, as if by overcrowding.
3. Any live cell with two or three live neighbours lives on to the next generation.
4. Any dead cell with exactly three live neighbours becomes a live cell.
The initial pattern constitutes the seed of the system. The first generation is created by applying the above rules simultaneously to every cell in the seed—births and deaths happen simultaneously, and the discrete moment at which this happens is sometimes called a tick (in other words, each generation is a pure function of the one before). The rules continue to be applied repeatedly to create further generations.
--However, for our purposes, we will assign a size to the game
Notice that in this problem, at each step or
Note: In this question, there should be a need for shared state between worker threads while the problem is being solved.
Example:
-Conway Game of Life-
From Wikipedia:
The universe of the Game of Life is an infinite two-dimensional orthogonal grid of square cells, each of which is in one of two possible states, live or dead. Every cell interacts with its eight neighbors, which are the cells that are directly horizontally, vertically, or diagonally adjacent. At each step in time, the following transitions occur:
1. Any live cell with fewer than two live neighbours dies, as if caused by underpopulation.
2. Any live cell with more than three live neighbours dies, as if by overcrowding.
3. Any live cell with two or three live neighbours lives on to the next generation.
4. Any dead cell with exactly three live neighbours becomes a live cell.
The initial pattern constitutes the seed of the system. The first generation is created by applying the above rules simultaneously to every cell in the seed—births and deaths happen simultaneously, and the discrete moment at which this happens is sometimes called a tick (in other words, each generation is a pure function of the one before). The rules continue to be applied repeatedly to create further generations.
--However, for our purposes, we will assign a size to the game
"board": 2^k * 2^k . That is, the board should be easy to subdivide.
Notice that in this problem, at each step or
"tick", each thread/process will need to share data with its neighborhood.
fsharp
/// Represents a single cell, along with the basic transition rule
type State =
| Alive
| Dead
member this.Transition numLiveNeighbors =
match this with
| Alive when numLiveNeighbors < 2 -> Dead
| Alive when numLiveNeighbors > 3 -> Dead
| Alive -> Alive
| Dead when numLiveNeighbors = 3 -> Alive
| _ -> Dead
member this.ToChar() =
match this with
| Alive -> '*'
| Dead -> ' '
static member OfChar = function
| ' ' -> Dead
| _ -> Alive
type Board (board: State[,]) =
member this.Item
with get(i,j) = board.[i,j]
and set (i,j) v = board.[i,j] <- v
member this.Length1 = Array2D.length1 board
member this.Length2 = Array2D.length2 board
member this.CountLiveNeighbors(i, j) =
[| (-1,-1); (-1,0); (-1,1); (0,-1); (0,1); (1,-1); (1,0); (1,1) |]
|> Array.sumBy (fun (di,dj) ->
if (i + di) > 0 && (i + di) < this.Length1 && (j+dj) > 0 && (j+dj) < this.Length2 then
match board.[i+di,j+dj] with
| Alive -> 1
| _ -> 0
else
0
)
member this.Clone() = Board(Array2D.copy board)
override this.ToString() =
[|
for i in 0 .. this.Length1 - 1 do
let l = [| for j in 0 .. this.Length2 - 1 do yield board.[i,j].ToChar() |]
yield new String(l)
|]
|> String.concat ("\n")
static member OfString (s: string) =
let states =
s.Split('\n')
|> Array.map (fun line -> line.ToCharArray() |> Array.map State.OfChar)
Board (Array2D.init states.Length states.[0].Length (fun i j -> states.[i].[j]))
static member Update (inboard: Board) =
let outboard = inboard.Clone()
let Worker (i1,i2,j1,j2) =
for i in i1 .. i2 do
for j in j1 .. j2 do
outboard.[i,j] <-
inboard.CountLiveNeighbors(i, j)
|> inboard.[i,j].Transition
let N1 = inboard.Length1 / 2
let N2 = inboard.Length2 / 2
[| (0,N1,0,N2); (N1+1,inboard.Length1-1,0,N2); (0,N1,N2+1,inboard.Length2-1); (N1+1,inboard.Length1-1,N2+1,inboard.Length2-1) |]
|> Array.map (fun bounds -> async { Worker bounds})
|> Async.Parallel
|> Async.RunSynchronously
|> ignore
outboard
let blinker = " \n * \n * \n * \n " |> Board.OfString
do
let after1cycles =
blinker
|> Board.Update
let after3cycles =
after1cycles
|> Board.Update
|> Board.Update
printfn "%s" (after3cycles.ToString())
type State =
| Alive
| Dead
member this.Transition numLiveNeighbors =
match this with
| Alive when numLiveNeighbors < 2 -> Dead
| Alive when numLiveNeighbors > 3 -> Dead
| Alive -> Alive
| Dead when numLiveNeighbors = 3 -> Alive
| _ -> Dead
member this.ToChar() =
match this with
| Alive -> '*'
| Dead -> ' '
static member OfChar = function
| ' ' -> Dead
| _ -> Alive
type Board (board: State[,]) =
member this.Item
with get(i,j) = board.[i,j]
and set (i,j) v = board.[i,j] <- v
member this.Length1 = Array2D.length1 board
member this.Length2 = Array2D.length2 board
member this.CountLiveNeighbors(i, j) =
[| (-1,-1); (-1,0); (-1,1); (0,-1); (0,1); (1,-1); (1,0); (1,1) |]
|> Array.sumBy (fun (di,dj) ->
if (i + di) > 0 && (i + di) < this.Length1 && (j+dj) > 0 && (j+dj) < this.Length2 then
match board.[i+di,j+dj] with
| Alive -> 1
| _ -> 0
else
0
)
member this.Clone() = Board(Array2D.copy board)
override this.ToString() =
[|
for i in 0 .. this.Length1 - 1 do
let l = [| for j in 0 .. this.Length2 - 1 do yield board.[i,j].ToChar() |]
yield new String(l)
|]
|> String.concat ("\n")
static member OfString (s: string) =
let states =
s.Split('\n')
|> Array.map (fun line -> line.ToCharArray() |> Array.map State.OfChar)
Board (Array2D.init states.Length states.[0].Length (fun i j -> states.[i].[j]))
static member Update (inboard: Board) =
let outboard = inboard.Clone()
let Worker (i1,i2,j1,j2) =
for i in i1 .. i2 do
for j in j1 .. j2 do
outboard.[i,j] <-
inboard.CountLiveNeighbors(i, j)
|> inboard.[i,j].Transition
let N1 = inboard.Length1 / 2
let N2 = inboard.Length2 / 2
[| (0,N1,0,N2); (N1+1,inboard.Length1-1,0,N2); (0,N1,N2+1,inboard.Length2-1); (N1+1,inboard.Length1-1,N2+1,inboard.Length2-1) |]
|> Array.map (fun bounds -> async { Worker bounds})
|> Async.Parallel
|> Async.RunSynchronously
|> ignore
outboard
let blinker = " \n * \n * \n * \n " |> Board.OfString
do
let after1cycles =
blinker
|> Board.Update
let after3cycles =
after1cycles
|> Board.Update
|> Board.Update
printfn "%s" (after3cycles.ToString())
groovy
// some crude assumptions made for size and amount of parallelism
enum State { ALIVE, DEAD }
import static State.*
seed = '''\
* *
** **
** *
*
**
***
**
* \
'''
def computeNextGen(inboard, outboard, n) {
// crudely split into 4 chunks but could be smarter if we wanted
int half = n/2
def t1 = Thread.start { computeNextGen(inboard, outboard, n, 0, half, 0, half) }
def t2 = Thread.start { computeNextGen(inboard, outboard, n, 0, half, half, n) }
def t3 = Thread.start { computeNextGen(inboard, outboard, n, half, n, 0, half) }
def t4 = Thread.start { computeNextGen(inboard, outboard, n, half, n, half, n) }
[t1, t2, t3, t4].each{ it.join() }
}
def computeNextGen(inboard, outboard, n, minx, maxx, miny, maxy) {
for (int i = minx; i < maxx; i++)
for (int j = 0; j < maxy; j++)
if (i == 0 || i == n-1 || j == 0 || j == n-1)
outboard[i][j] = DEAD
for (int i = minx; i < maxx; i++) {
for (int j = miny; j < maxy; j++) {
if (i == 0 || i == n-1 || j == 0 || j == n-1)
continue
int count = 0
[[-1, 0, 1], [-1, 0, 1]].combinations().each{ dx, dy ->
if ((dx || dy) && inboard[i+dx][j+dy] == ALIVE) count++
}
switch(count) {
case {count == 3}:
case {inboard[i][j] == ALIVE && count == 2}:
outboard[i][j] = ALIVE; break
default:
outboard[i][j] = DEAD
}
}
}
}
void printBoard(board) {
println '--------'
println board*.collect{ it == DEAD ? ' ' : '*' }*.join().join('\n')
}
void initBoard(seed, board) {
def row = 0
seed.readLines().each { line ->
def col = 0
line.each { ch ->
board[row][col++] = ch == '*' ? ALIVE : DEAD
}
row++
}
}
def N = 8
def NUM_CYCLES = 3
def board1 = new State[N][N]
def board2 = new State[N][N]
initBoard(seed, board1)
NUM_CYCLES.times {
computeNextGen board1, board2, N
printBoard board2
computeNextGen board2, board1, N
printBoard board1
}
enum State { ALIVE, DEAD }
import static State.*
seed = '''\
* *
** **
** *
*
**
***
**
* \
'''
def computeNextGen(inboard, outboard, n) {
// crudely split into 4 chunks but could be smarter if we wanted
int half = n/2
def t1 = Thread.start { computeNextGen(inboard, outboard, n, 0, half, 0, half) }
def t2 = Thread.start { computeNextGen(inboard, outboard, n, 0, half, half, n) }
def t3 = Thread.start { computeNextGen(inboard, outboard, n, half, n, 0, half) }
def t4 = Thread.start { computeNextGen(inboard, outboard, n, half, n, half, n) }
[t1, t2, t3, t4].each{ it.join() }
}
def computeNextGen(inboard, outboard, n, minx, maxx, miny, maxy) {
for (int i = minx; i < maxx; i++)
for (int j = 0; j < maxy; j++)
if (i == 0 || i == n-1 || j == 0 || j == n-1)
outboard[i][j] = DEAD
for (int i = minx; i < maxx; i++) {
for (int j = miny; j < maxy; j++) {
if (i == 0 || i == n-1 || j == 0 || j == n-1)
continue
int count = 0
[[-1, 0, 1], [-1, 0, 1]].combinations().each{ dx, dy ->
if ((dx || dy) && inboard[i+dx][j+dy] == ALIVE) count++
}
switch(count) {
case {count == 3}:
case {inboard[i][j] == ALIVE && count == 2}:
outboard[i][j] = ALIVE; break
default:
outboard[i][j] = DEAD
}
}
}
}
void printBoard(board) {
println '--------'
println board*.collect{ it == DEAD ? ' ' : '*' }*.join().join('\n')
}
void initBoard(seed, board) {
def row = 0
seed.readLines().each { line ->
def col = 0
line.each { ch ->
board[row][col++] = ch == '*' ? ALIVE : DEAD
}
row++
}
}
def N = 8
def NUM_CYCLES = 3
def board1 = new State[N][N]
def board2 = new State[N][N]
initBoard(seed, board1)
NUM_CYCLES.times {
computeNextGen board1, board2, N
printBoard board2
computeNextGen board2, board1, N
printBoard board1
}
