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Check if a string matches with groups
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ruby
csharp
clojure
fsharp
fantom
groovy
groovy 1.6.1+
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"two" if "one two three" matches /one (.*) three/
puts $1 if "one two three"=~/^one (.*) three$/
using System;
using System.Text.RegularExpressions;
public class RegexBackReference {
public static void Main() {
var oneTwoThree = "one two three";
var pattern = "one (.*) three";
Match match = Regex.Match(oneTwoThree, pattern);
// group 0 is the entire match. 1 is the first backreference
Console.WriteLine(match.Groups[1]);
}
}
using System.Text.RegularExpressions;
public class RegexBackReference {
public static void Main() {
var oneTwoThree = "one two three";
var pattern = "one (.*) three";
Match match = Regex.Match(oneTwoThree, pattern);
// group 0 is the entire match. 1 is the first backreference
Console.WriteLine(match.Groups[1]);
}
}
(if-let [groups (re-matches #"one (.*) three" "one two three")]
(println (second groups)))
(println (second groups)))
let regmatch = (Regex.Match("one two three", "one (.*) three"))
if regmatch.Success then (printfn "%s" (regmatch.Groups.[1].Captures.[0].ToString()))
if regmatch.Success then (printfn "%s" (regmatch.Groups.[1].Captures.[0].ToString()))
m := Regex<|one (.*) three|>.matcher("one two three")
if (m.matches)
echo("${m.group(1)}")
if (m.matches)
echo("${m.group(1)}")
matcher = ("one two three" =~ /one (.*) three/)
if (matcher) println matcher[0][1]
if (matcher) println matcher[0][1]
match = "one two three".find("one (.*) three") { it[1] }
if (match) println match
if (match) println match
Submit a new solution for ruby, csharp, clojure, fsharp ...
There are 12 other solutions in additional languages (cpp, erlang, go, haskell ...)
