View Problem
Reverse the characters in a string
Given the string 
ruby
erlang
erlang
csharp 3.0
cpp C++/CLI .NET 2.0
cpp
cpp
cpp
go
go go1
Submit a new solution for ruby, erlang, csharp, cpp ...
There are 16 other solutions in additional languages (clojure, fantom, fsharp, groovy ...)
"reverse me", produce the string "em esrever"
puts "reverse me".reverse
Reversed = lists:reverse("reverse me"),
Reversed = revchars("reverse me"),
var str = "reverse me";
Console.WriteLine(new String(str.Reverse().ToArray()));
Console.WriteLine(new String(str.Reverse().ToArray()));
String^ s = "reverse me";
array<Char>^ sa = s->ToCharArray();
Array::Reverse(sa);
String^ sr = gcnew String(sa);
array<Char>^ sa = s->ToCharArray();
Array::Reverse(sa);
String^ sr = gcnew String(sa);
std::string s = "reverse me";
std::reverse(s.begin(), s.end());
std::reverse(s.begin(), s.end());
std::string s = "reverse me";
std::string sr(s.rbegin(), s.rend());
std::string sr(s.rbegin(), s.rend());
std::string s = "reverse me";
std::swap_ranges(s.begin(), (s.begin() + s.size() / 2), s.rbegin());
std::swap_ranges(s.begin(), (s.begin() + s.size() / 2), s.rbegin());
package main;
import "utf8";
import "fmt";
func reverse(s string) string {
o := make([]int, utf8.RuneCountInString(s))
i := len(o)
for _, c := range s {
i--
o[i] = c
}
return string(o)
}
func main() {
fmt.Print(reverse("reverse me"));
}
import "utf8";
import "fmt";
func reverse(s string) string {
o := make([]int, utf8.RuneCountInString(s))
i := len(o)
for _, c := range s {
i--
o[i] = c
}
return string(o)
}
func main() {
fmt.Print(reverse("reverse me"));
}
func Reverse(s string) string {
runes := []rune(s)
for i, j := 0, len(runes)-1; i < j; i, j = i+1, j-1 {
runes[i], runes[j] = runes[j], runes[i]
}
return string(runes)
}
runes := []rune(s)
for i, j := 0, len(runes)-1; i < j; i, j = i+1, j-1 {
runes[i], runes[j] = runes[j], runes[i]
}
return string(runes)
}
Submit a new solution for ruby, erlang, csharp, cpp ...
There are 16 other solutions in additional languages (clojure, fantom, fsharp, groovy ...)
