View Problem
Reverse the characters in a string
Given the string 
ruby
erlang
erlang
csharp 3.0
fsharp
fsharp F# 2.0 Interactive Build 4.0.30319.1
cpp C++/CLI .NET 2.0
cpp
cpp
cpp
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There are 16 other solutions in additional languages (clojure, fantom, go, groovy ...)
"reverse me", produce the string "em esrever"
puts "reverse me".reverse
Reversed = lists:reverse("reverse me"),
Reversed = revchars("reverse me"),
var str = "reverse me";
Console.WriteLine(new String(str.Reverse().ToArray()));
Console.WriteLine(new String(str.Reverse().ToArray()));
let reversed = new String (Array.rev ("reverse me".ToCharArray()))
let word = "reverse me"
//reverse the word
let reversedword =
word.ToCharArray()
|> Array.fold(fun acc x -> x::acc) []
//reverse the word
let reversedword =
word.ToCharArray()
|> Array.fold(fun acc x -> x::acc) []
String^ s = "reverse me";
array<Char>^ sa = s->ToCharArray();
Array::Reverse(sa);
String^ sr = gcnew String(sa);
array<Char>^ sa = s->ToCharArray();
Array::Reverse(sa);
String^ sr = gcnew String(sa);
std::string s = "reverse me";
std::reverse(s.begin(), s.end());
std::reverse(s.begin(), s.end());
std::string s = "reverse me";
std::string sr(s.rbegin(), s.rend());
std::string sr(s.rbegin(), s.rend());
std::string s = "reverse me";
std::swap_ranges(s.begin(), (s.begin() + s.size() / 2), s.rbegin());
std::swap_ranges(s.begin(), (s.begin() + s.size() / 2), s.rbegin());
Submit a new solution for ruby, erlang, csharp, fsharp ...
There are 16 other solutions in additional languages (clojure, fantom, go, groovy ...)
