View Problem
Perform an action a fixed number of times with a counter
Display the string 
ruby
erlang
erlang
csharp
fsharp
fsharp
groovy
java
Submit a new solution for ruby, erlang, csharp, fsharp ...
There are 14 other solutions in additional languages (clojure, cpp, fantom, haskell ...)
"10 .. 9 .. 8 .. 7 .. 6 .. 5 .. 4 .. 3 .. 2 .. 1 .. Liftoff!"
10.downto(1) { |n| print n, " .. " }
puts "Liftoff!"
puts "Liftoff!"
fromto(10, 1, -1, fun (X) -> io:format("~B .. ", [X]) end), io:format("Liftoff!~n").
lists:foreach(fun (X) -> io:format("~B .. ", [X]) end, lists:seq(10, 1, -1)), io:format("Liftoff!~n").
for (int i = 10; i > 0; i--)
{
Console.Write("{0} .. ", i);
}
Console.WriteLine("Liftoff!");
{
Console.Write("{0} .. ", i);
}
Console.WriteLine("Liftoff!");
for i = 10 downto 1 do printf "%d .. " i done
printfn "Liftoff!"
printfn "Liftoff!"
// Repetition via ranging over a Sequence type
for i in {10 .. -1 .. 1} do printf "%d .. " i done ; printfn "Liftoff!"
for i in {10 .. -1 .. 1} do printf "%d .. " i done ; printfn "Liftoff!"
10.downto(1) { print it + " .. " }
println "Liftoff!"
println "Liftoff!"
for(int i=10; i>=1; i--) {
System.out.print(i + " .. ");
}
System.out.print("Liftoff!");
System.out.print(i + " .. ");
}
System.out.print("Liftoff!");
Submit a new solution for ruby, erlang, csharp, fsharp ...
There are 14 other solutions in additional languages (clojure, cpp, fantom, haskell ...)
