View Problem
Process a file one line at a time
Open the source file to your solution and print each line in the file, prefixed by the line number, like:
1> First line of file
2> Second line of file
3> Third line of file
scala
scala
Submit a new solution for scala
There are 26 other solutions in additional languages (clojure, cpp, csharp, erlang ...)
1> First line of file
2> Second line of file
3> Third line of file
val source = Source.fromFile(new File("Solution468.scala")).getLines
var n = 1 ; while (source.hasNext) { printf("%d> %s", n, source.next) ; n += 1 }
var n = 1 ; while (source.hasNext) { printf("%d> %s", n, source.next) ; n += 1 }
val source = Source.fromFile(new File("Solution469.scala")).getLines
for ((line, n) <- source zipWithIndex) { printf("%d> %s", (n + 1), line) }
for ((line, n) <- source zipWithIndex) { printf("%d> %s", (n + 1), line) }
Submit a new solution for scala
There are 26 other solutions in additional languages (clojure, cpp, csharp, erlang ...)
